Abstract
Ustochrept soil was collected from a major potato-growing area in Pakistan for a potassium (K) adsorption isotherm experiment. Adsorption data were fitted to Freundlich and Langmuir adsorption models. Results showed that the Freundlich model (R2 = 0.96**) fit the data better than did the Langmuir model. Fertilizer rates were calculated based on the Freundlich model and targeted solution K levels at 0, 3, 6, 9, 12, 15, 18, 21, 24, and 27 mg K L−1. A field experiment was then conducted on the soil to assess the effect of various soil solution K levels (0–27 mg L−1, with K fertilizer rates at 0, 24, 49, 75, 101, 128, 155, 182, 210, and 237 kg ha−1), on tuber yield and quality along with 300 kg N and 250 kg P2O5 ha−1 as basal doses. Yield response models (linear plus plateau, quadratic, square root, quadratic plus plateau, and exponential) were used to calculate the optimal fertilizer rate for potato crop. Linear plus plateau model fit the data with less bias than the other models. There was a significant effect of K use on the yield and quality of potatoes. Potassium fertilizer application at 130 kg K ha−1, which is equivalent to a soil solution level of 12 mg K L−1, maximized the tuber yield of potato. However, for the improvement in tuber dry matter, reducing sugars, protein contents, and starch contents, the soil solution K level required was as high as14.62 mg L−1 (157 kg ha−1). Even greater rate of K, 17.74 mg L−1 (190 kg ha−1), was needed to maximize vitamin C content in potato.
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Claims 10
Claim · model-written summary
Freundlich adsorption model fit the soil data better than Langmuir, with R2 = 0.96**.
- Taxon
- Potato
Solanum tuberosumt0 - Outcome
- fit the datae0
- Direction
- bettere0
- Value
- R2 = 0.96**e0
- Comparator
- Langmuir modele0
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“the Freundlich model (R2 = 0.96**) fit the data better than did the Langmuir model.”
t0“Potato Crop”
Claim · model-written summary
The linear plus plateau yield response model fit with less bias than the other models.
- Taxon
- PotatoSolanum tuberosumt0
- Outcome
- fit the data with less biase0
- Direction
- less biase0
- Comparator
- other modelse0
Not reportedValue
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“Linear plus plateau model fit the data with less bias than the other models.”
t0“Potato Crop”
Claim · model-written summary
Potassium use significantly affected potato yield.
- Taxon
- potatoesSolanum tuberosume0
- Treatment
- K usee0
- Outcome
- yielde0
Not reportedComparatorDirection
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“There was a significant effect of K use on the yield and quality of potatoes.”
Claim · model-written summary
Potassium use significantly affected potato quality.
- Taxon
- potatoesSolanum tuberosume0
- Treatment
- K usee0
- Outcome
- qualitye0
Not reportedComparatorDirection
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“There was a significant effect of K use on the yield and quality of potatoes.”
Claim · model-written summary
130 kg K ha−1 maximized potato tuber yield, corresponding to 12 mg K L−1 in soil solution.
- Taxon
- potatoSolanum tuberosume0
- Treatment
- Potassium fertilizer application at 130 kg K ha−1e0
- Outcome
- tuber yielde0
- Direction
- maximizede0
- Value
- 12 mg K L−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“Potassium fertilizer application at 130 kg K ha−1, which is equivalent to a soil solution level of 12 mg K L−1, maximized the tuber yield of potato.”
Claim · model-written summary
Improving tuber dry matter required a soil solution K level as high as 14.62 mg L−1, equivalent to 157 kg ha−1.
- Taxon
- PotatoSolanum tuberosumt0
- Treatment
- soil solution K levele0
- Outcome
- tuber dry mattere0
- Direction
- improvemente0
- Value
- 14.62 mg L−1e0
- Qualifier
- 157 kg ha−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“for the improvement in tuber dry matter, reducing sugars, protein contents, and starch contents, the soil solution K level required was as high as14.62 mg L−1 (157 kg ha−1).”
t0“Potato Crop”
Claim · model-written summary
Improving tuber reducing sugars required a soil solution K level as high as 14.62 mg L−1.
- Taxon
- PotatoSolanum tuberosumt0
- Treatment
- soil solution K levele0
- Outcome
- reducing sugarse0
- Direction
- improvemente0
- Value
- 14.62 mg L−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“for the improvement in tuber dry matter, reducing sugars, protein contents, and starch contents, the soil solution K level required was as high as14.62 mg L−1 (157 kg ha−1).”
t0“Potato Crop”
Claim · model-written summary
Improving tuber protein contents required a soil solution K level as high as 14.62 mg L−1.
- Taxon
- PotatoSolanum tuberosumt0
- Treatment
- soil solution K levele0
- Outcome
- protein contentse0
- Direction
- improvemente0
- Value
- 14.62 mg L−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“for the improvement in tuber dry matter, reducing sugars, protein contents, and starch contents, the soil solution K level required was as high as14.62 mg L−1 (157 kg ha−1).”
t0“Potato Crop”
Claim · model-written summary
Improving tuber starch contents required a soil solution K level as high as 14.62 mg L−1.
- Taxon
- PotatoSolanum tuberosumt0
- Treatment
- soil solution K levele0
- Outcome
- starch contentse0
- Direction
- improvemente0
- Value
- 14.62 mg L−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“for the improvement in tuber dry matter, reducing sugars, protein contents, and starch contents, the soil solution K level required was as high as14.62 mg L−1 (157 kg ha−1).”
t0“Potato Crop”
Claim · model-written summary
Maximizing potato vitamin C required 17.74 mg L−1 soil solution K, equivalent to 190 kg ha−1.
- Taxon
- potatoSolanum tuberosume0
- Treatment
- rate of Ke0
- Outcome
- vitamin C contente0
- Direction
- maximizee0
- Value
- 17.74 mg L−1e0
- Qualifier
- 190 kg ha−1e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
Verbatim
e0“Even greater rate of K, 17.74 mg L−1 (190 kg ha−1), was needed to maximize vitamin C content in potato.”
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